How to delete multimple Snapshots with one command?

LXD
1

Hi, I was wondering if there is a way to delete multiple snapshots with one command, I’ve been benchmarking a new LXD node and I had set the snapshots to every minute for the default profile, now I have tons of snapshots for each container and I wanted to delete them.

I’ve tried this but doesn’t work:

lxc rm con01/snap*
and
lxc rm con01/*

but it doesn’t like the asterisc
Error: Failed to fetch snapshot “snap*” of instance “con01” in project “default”: No such object

Any way to do so without having to use ZFS commands?

Thank you!

2

There is no wildcard support in this command or really in much any LXD command.

Your best bet would be something like:

lxc query /1.0/instances/con01/snapshots?recursion=1 | jq -r ‘.[].name’ | while read line; do lxc delete con01/$line; done

So effectively retrieving the list of snapshots, filtering it whatever way you want and then calling lxc delete on those.

3 Likes
3

OK, I guess it is time to learn how to work with the database!

Thanks @stgraber

4

Option 2 :slight_smile:

lxc info con01 | awk ‘{print $1}’ | grep snap | xargs -I SNAP lxc delete con01/SNAP

Regards
G

1 Like
5

I’ve made this little python script that print all delete snapshot commands that can be made on all running containers:

import os
stream = os.popen("lxc list --format=json | jq -r '.[] | select(.state.status == \"Running\") | .name '")
output = stream.read()
for cont in output.split("\n"):
    if cont:
        lss=os.popen("lxc query /1.0/instances/{}/snapshots?recursion=1 | jq -r '.[].name' ".format(cont))
        lss=lss.read()
        lssn=lss.split("\n")
        for lss in lssn:
            if lss:
                print("lxc delete {}/{}".format(cont,lss))